Water, Sodium Laureth Sulfate, Sodium Lauryl Sulfate, Glycol Distearate, Cocamidopropyl Betaine, Dimethicone, Cetyl Alcohol, Betaine, Laureth-23, Laureth-3, Coconut Oil - Cocos Nucifera, Aloe Barbadensis Leaf Extract, Silk Amino Acids, Jojoba Seed Oil - Simmondsia Chinensis, Polyquaternium-7, Cocamide MEA, Bis-Methoxypropylamido Isodocosane, Glyceryl Oleate, Glycine, Sodium Hydroxide, Methylchloroisothiazolinone, Methylisothiazolinone, Sodium Xylenesulfonate, Malic Acid, Benzyl Alcohol, Mineral Oil, Guar Hydroxypropyltrimonium Chloride, Sodium Chloride, Disodium EDTA, Fragrance, Caramel.
John Frieda Brilliant Brunette Lustrous Touch Smoothing Shampoo with Satin Finishers smoothes and softens hair for silky perfection to reveal shiny brown tones-see and feel your hair's true beauty!
- Satin Finishers contain jojoba oil and silk amino acids
- Bonds to hair fibers, seals the cuticle, and locks in moisture
- Smoothes and aligns hair strands to reflect more light and increase shine
- Deeply hydrate hair for smooth, soft, brown strands with glossy sleekness
- For all shades of natural, color-treated, or highlighted brunette hair
Apply shampoo to wet hair. Gently massage and work into a rich lather. Rinse thoroughly and repeat if necessary. For optimal smoothing, follow with the Brilliant Brunette Lustrous Touch Smoothing Conditioner.
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